J'ai perdu des images créées avec les cameras de mon appareil Canon et de mon mobile Nexus 5.
J'ai lu la doc, cependant l'exemple affiche la valeur '0' pour le paramètre 'offset of the signature'.
Peut-on utiliser une valeur autre que '0' pour ce paramètre? Exemple:
Content of '.photorec.sig' (en se fiant aux 2 dump qui suivent).
jpg DC 0x43616e6f6e20506f77657253686f742053583530204853
jpg BE 0x4e657875732035
Code: Select all
sylvie@blackPC:~$ hexdump -C /home/sylvie/Documents/00_inondation_nov_2017/03_photos/Canon/IMG_0937.JPG | more
00000000 ff d8 ff e1 35 fe 45 78 69 66 00 00 49 49 2a 00 |....5.Exif..II*.|
00000010 08 00 00 00 0d 00 0e 01 02 00 20 00 00 00 aa 00 |.......... .....|
00000020 00 00 0f 01 02 00 06 00 00 00 ca 00 00 00 10 01 |................|
00000030 02 00 18 00 00 00 d0 00 00 00 12 01 03 00 01 00 |................|
00000040 00 00 01 00 00 00 1a 01 05 00 01 00 00 00 e8 00 |................|
00000050 00 00 1b 01 05 00 01 00 00 00 f0 00 00 00 28 01 |..............(.|
00000060 03 00 01 00 00 00 02 00 00 00 32 01 02 00 14 00 |..........2.....|
00000070 00 00 f8 00 00 00 3b 01 02 00 01 00 00 00 00 00 |......;.........|
00000080 00 00 13 02 03 00 01 00 00 00 02 00 00 00 98 82 |................|
00000090 02 00 01 00 00 00 00 00 80 43 69 87 04 00 01 00 |.........Ci.....|
000000a0 00 00 0c 01 00 00 25 88 04 00 01 00 00 00 88 13 |......%.........|
000000b0 00 00 88 14 00 00 20 20 20 20 20 20 20 20 20 20 |...... |
000000c0 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 | |
000000d0 20 20 20 20 20 00 43 61 6e 6f 6e 00 43 61 6e 6f | .Canon.Cano|
000000e0 6e 20 50 6f 77 65 72 53 68 6f 74 20 53 58 35 30 |n PowerShot SX50|
000000f0 20 48 53 00 b4 00 00 00 01 00 00 00 b4 00 00 00 | HS.............|
...
jpg DC 0x43616e6f6e20506f77657253686f742053583530204853
Code: Select all
sylvie@blackPC:~$ hexdump -C /home/sylvie/Documents/00_inondation_nov_2017/03_photos/N5/IMG_20171103_060616.jpg | more
00000000 ff d8 ff e1 76 ec 45 78 69 66 00 00 4d 4d 00 2a |....v.Exif..MM.*|
00000010 00 00 00 08 00 0c 01 32 00 02 00 00 00 14 00 00 |.......2........|
00000020 00 9e 88 25 00 04 00 00 00 01 00 00 02 43 01 10 |...%.........C..|
00000030 00 02 00 00 00 08 00 00 00 b2 01 00 00 04 00 00 |................|
00000040 00 01 00 00 09 90 02 13 00 03 00 00 00 01 00 01 |................|
00000050 00 00 01 28 00 03 00 00 00 01 00 02 00 00 01 01 |...(............|
00000060 00 04 00 00 00 01 00 00 0c c0 01 1b 00 05 00 00 |................|
00000070 00 01 00 00 00 ba 01 12 00 03 00 00 00 01 00 01 |................|
00000080 00 00 87 69 00 04 00 00 00 01 00 00 00 ca 01 1a |...i............|
00000090 00 05 00 00 00 01 00 00 00 c2 01 0f 00 02 00 00 |................|
000000a0 00 04 4c 47 45 00 00 00 02 49 32 30 31 37 3a 31 |..LGE....I2017:1|
000000b0 31 3a 30 33 20 30 36 3a 30 36 3a 31 38 00 4e 65 |1:03 06:06:18.Ne|
000000c0 78 75 73 20 35 00 00 00 00 48 00 00 00 01 00 00 |xus 5....H......|
000000d0 00 48 00 00 00 01 00 14 a0 01 00 03 00 00 00 01 |.H..............|
...
jpg BE 0x4e657875732035
Merci à l'avance pour votre aide.